Matematika selesaikan penjumlaha berikut dalam bentuk pecahan biasa atau pecahan campuran a.2/5 + 3 1/4= b.2/7 + 0,4 = c.3/5 + 30% = d.2 1/6 + 1,2 = e.60% + 0,12 = f.0,1 + 8% = g.0,625 + 75% = h.2 1/6 + 0,15 = ​

mollyhackettulv – March 18, 2023

selesaikan penjumlaha berikut dalam bentuk pecahan biasa atau pecahan campuran a.2/5 + 3 1/4= b.2/7 + 0,4 = c.3/5 + 30% = d.2 1/6 + 1,2 = e.60% + 0,12 = f.0,1 + 8% = g.0,625 + 75% = h.2 1/6 + 0,15 = ​

Jawaban:

JADIKAN JAWABAN TERBAIK

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A.

[tex] \frac{2}{5} + 3 \frac{1}{4} = [/tex]

[tex] \frac{2}{5} + \frac{13}{4} = [/tex]

[tex] \frac{8}{20} + \frac{65}{20} = [/tex]

[tex] \frac{73}{20} = 3 \frac{13}{20} [/tex]

B.

[tex] \frac{2}{7} + 0.4 = [/tex]

[tex] \frac{2}{7} + \frac{2}{5} = [/tex]

[tex] \frac{10}{35} + \frac{14}{ 35} = [/tex]

[tex] \frac{24}{35} [/tex]

C.

[tex] \frac{3}{5} + 30\% = [/tex]

[tex] \frac{3}{5} + \frac{3}{10} = [/tex]

[tex] \frac{6}{10} + \frac{3}{10} = [/tex]

[tex] \frac{9}{10} [/tex]

D.

[tex]2 \frac{1}{6} + 1.2 = [/tex]

[tex] \frac{13}{6} + \frac{6}{5} = [/tex]

[tex] \frac{65}{30} + \frac{36}{30} = [/tex]

[tex] \frac{101}{30} = 3 \frac{11}{30} [/tex]

E.

[tex]60\% + 0.12 = [/tex]

[tex] \frac{3}{5} + \frac{6}{50} = [/tex]

[tex] \frac{30}{50} + \frac{6}{50} = [/tex]

[tex] \frac{36}{50} = \frac{18}{25} [/tex]

F.

[tex]0.1 + 8\% = [/tex]

[tex] \frac{1}{10} + \frac{2}{25} = [/tex]

[tex] \frac{5}{50} + \frac{4}{50} = [/tex]

[tex] \frac{9}{50} [/tex]

G.

[tex]0.625 + 75\% = [/tex]

[tex] \frac{5}{8} + \frac{3}{4} = [/tex]

[tex] \frac{5}{8} + \frac{6}{8} = [/tex]

[tex] \frac{11}{8} = 1 \frac{3}{8} [/tex]

H.

[tex]2 \frac{1}{6} + 0.15 = [/tex]

[tex] \frac{13}{6} + \frac{3}{20} = [/tex]

[tex] \frac{130}{60} + \frac{9}{60} = [/tex]

[tex] \frac{139}{60} = 2\frac{19}{60} [/tex]

SEMOGA BERMANFAAT

MAAF KALAU SALAH

JADIKAN JAWABAN TERBAIK

#belajarmatematikabersama100gemarbantu100

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